im getting a converter custom built and they need to know an estimate of the touque produced . i estimate hp at flywheel is 400 but i need touque also

351 6inch rods single plane 750 vac sec
2v open heads 4v valves
9.5 compressaion
stage 4 solid cam 3200 - 7500 rev range
inlet 0.569 lift
exh 0.590 lift
4 into 1 headers into 3inch
c4 rear end 3.6:1

converter is about 3500-4000stall

can anyone help

Torque = (Horsepower * 5252) / RPM

This is an american formula so will all be imperial.

So, lets say engine hp is 400 @ 5000RPM

Torque = 2,100,800 / 5000
= 420 foot-pounds

Substitute the correct RPM in there and you should be on the mark.

Newton metres should be around 0.74 ft/lb so 1 ft/lb = 1.3558Nm

In the above example, 400 hp @ 5000rpm will be 570Nm

Just remember, peak horsepower will not be at the same point as peak torque.

i used 6000rpm as its a big cam and i came up with 350 ft
i asked the same question on fordforum and someone who sounds like he knows what hes talkin about said 350 also
thanks for your input

in this case it most likly will not be

but it can happen

ive given the figure of 350 ft to him and hes going off that
its only a t5rans out and 100 bucks to change pumpand /or stator anyway
thanks for the help